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Rate Laws, Arrhenius Equation - Experiments Peter Keusch, University of Regensburg | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
![]() This means that the rate of the reaction never changes; it's always equal to the value of the rate constant. Rearranging of equation (1) gives ![]() which on integration of both sides ![]() leads to When t  =  0, the concentration of A is [ A ] o. The constant of integration must be [ A ] o. Now the integrated form of zero-order kinetics can be written as follows Plotting [ A ] versus t will give a straight line with slope -k. For a general unimolecular reaction where A is a reactant and P is a product, the reaction rate expression for a first order reaction is ![]() This means that the reaction rate is proportional to the concentration of a single reactant raised to the first power. Separation of the variables in equation (1) ![]() and integration of equation (2) ![]() yields ![]() The constant of integration C can be evaluated by using boundary conditions. When t = 0, [ A ] = [ A ] o. [ A ] o is the initial concentration of A. Substituting the values above into equation (4) one obtains: ![]() ![]() Substituting equation (6) into equation (5) leads to the integrated rate law: ![]() Plotting ln [ A ] or ln [ A ] / [ A ] o against time creates a straight line with slope -k. The plot should be linear up to a conversion of about 90 %. Equation (7) can also be written as: ![]() The rate constant k can also be determined from the half-life t 1 / 2. Half-life is the time it takes for the concentration to fall from [ A ] o to [ A ] o / 2 ==> [ A ] = 1 / 2 [ A ] o. Equation (7) is rewritten as: ![]() Thus, half-life of a first order reaction is independent of the initial concentration of the reactant. A and B react to produce P: If the initial concentration of the reactant A is much larger than the concentration of B, the concentration of A will not change appreciably during the course of the reaction The concentration of the reactant in excess will remain almost constant. Thus the rate's dependence on  B  can be isolated and the rate law can be written ![]() Equation (1) represents the differential form of the rate law. Integration of this equation and evaluation of the integration constant C produces the corresponding integrated law. Substituting [ B ] = c into equation (1) yields ![]() Integrating equation (2) gives: ![]() Therefore ![]() ![]() If the decrease in concentration of B is followed by photometric measurement the Beer' Law must be taken into account. Combining equation (5) and Beer' Law ![]() c = Concentration of the absorbing species in solution, expressed in mol · L -1, d = Path length through the sample Io = Intensity of the initial light beam, I = Intensity of the transmitted light gives the relationship between k' and lnA: ![]() According to equation (7), a plot of lnA versus time should lead to a straight line whose slope is the pseudo-first order rate constant k'. The value of k' can then be divided by the known, constant concentration of the excess compound to obtain the true constant second order k: ![]() The pseudo-first order rate constant k' can be also determined from the half-life t 1 / 2. ![]() Measuring a second order reaction rate (see below) can be problematic: the concentrations of the two reactants must be followed simultaneously, which is more difficult; or measure one of them and calculate the other as a difference, which is less precise. A common solution for that problem is the pseudo first order approximation. As a general rule, a minimum of a 20-fold stoichiometric excess is necessary. A 50-fold or 100-fold stoichiometric excess is preferable. The rate of a second order reaction is proportional to either the concentration of a reactant squared, or the product of concentrations of two reactants. For the general case of a reaction between A and B, such that the rate of reaction will be given by ![]() 1. Initial concentrations of the two reactants are equal: Equation (1) can be written as: ![]() ![]() gives ![]() Provided that [ A ] = [ A ] o  at t = 0, the constant of integration C becomes equal to 1 / [ A ] o. Thus the second order integrated rate equation is ![]() A plot of 1 / [ A ] vs t produces a straight line with slope k and intercept 1 / [ A ]o. The plot should be linear up to a conversion of about 50 %. 2. Starting concentrations of the two reactants are different: If [ A ] o and [ B ] o are different the variable x is used. Noting that d[ A ] = - dx, the general rate equation (1) can be expressed by ![]() where [ A ] o - x = [ A ],   [ B ] o - x = [ B ]  and   x   is the decrease in the concentration of A and B respectively. In order to integrate the left-hand side of equation (6), it is necessary to perform a partial fraction expansion. The fraction on the left hand-side of equation below is splitted into a sum of simple fractions on the right hand-side. ![]() c' and c'' are two constants. Putting them back over a common denominator ![]() leads to ![]() Provided that - x (c' + c'') = 0 ![]() The equations above allow to determine the factors c' and c'': ![]() ![]() Using c', c'' notation equation (6) becomes the form ![]() whose integration ![]() results in ![]() where C is the constant of integration. Using the condition that x = 0, when t  =  0, the value of C can be found: ![]() and equation (15) becomes ![]() If [ A ] o > [ B ] o, then a plot of ![]() against t will have a positive slope, equal ([ A ] o - [ B ] o) · k. Because equivalent amounts of A and B are reacting, [ A ] can be expressed in terms of [ B ]: If the experimental method yields reactant concentrations rather than x, the equivalent form of equation (17) is ![]() The rate constant can be determined using equation (20), provided that the initial concentration of A is twice the initial concentration of B (see Kinetic equations - Reaction Second Order - Download PDF file): ![]() where xo = [ B ] o and x = [ B ] .
The Arrhenius equation is often written in the logarithmic form: ![]()
"Two-Point Form" of the Arrhenius Equation The activation energy can also be found algebraically by substituting two rate constants (k1, k2) and the two corresponding reaction temperatures (T1, T2) into the Arrhenius Equation (2). ![]() ![]() Substracting equation (4) from equation (3) results in ![]() Rerrangement of equation (5) and solving for E a yields ![]() References: How to Determine the Rate Law from Experimental Data Eyring Equation Conductivity Measurement
Photometric Measurement
Volume Measurement
Temperature Measurement
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